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Generated by the community from around the world
def reparto(monto):
carolina = 0.8*0.35*monto
diana = 0.35*monto
alfredo = 0.23*(diana + 0.25*monto)
cindy = 0.25*monto
pablo = monto - carolina - diana - alfredo - cindy
return carolina, diana, alfredo, cindy, pablo
reparto(1000)
def invoice(name, amount, **kwargs):
print(f"Name={name} Amount={amount}")
for k,v in kwargs.items():
print(f"{k} : {v}")
invoice("Paula", 100, tax=0.16, tip=1.2)
++
void intercambiar(int *a, int *b)
{
int temp;
temp = *a;
*a = *b;
*b = temp;
}
void main()
{
int a, b;
cout << "a = "; cin >> a;
cout << "b = "; cin >> b;
intercambiar(&a, &b);
cout << "a = " << a << endl;
cout << "b = " << b << endl;
}
Here's a simple example of a class in Java that has a method to increment a counter:
```java
public class Counter {
private int count;
public Counter() {
this.count = 0;
}
public void increment() {
this.count++;
}
public int getCount() {
return this.count;
}
public static void main(String[] args) {
Counter counter = new Counter();
System.out.println("Initial count: " + counter.getCount());
counter.increment();
System.out.println("Count after increment: " + counter.getCount());
counter.increment();
System.out.println("Count after second increment: " + counter.getCount());
}
}
```
In this example, the `Counter` class has a private integer field `count` to store the current count. The `increment` method increments the count by 1. The `getCount` method returns the current count.
When you run this code, it will output:
```
Initial count: 0
Count after increment: 1
Count after second increment: 2
```
This demonstrates that the `increment` method is working correctly and incrementing the counter each time it's called.
#include<stdio.h>
#include<stdlib.h>
#include<windows.h>
int main()
{
float producto[3][4][12],promedio[4][12];
int i,j,k;
for(i=0;i<3;i++)
{
for(j=0;j<4;j++)
{
for(k=0;k<12;k++)
{
printf("Ingrese venta del producto %d, mes %d, año %d\n",i+1,j+1,k+1);
scanf("%f",&producto[i][j][k]);
}
}
}
for(j=0;j<4;j++)
{
for(k=0;k<12;k++)
{
promedio[j][k]=0;
for(i=0;i<3;i++)
{
promedio[j][k
def tiempos(h, m):
h = h*60
return h + m
h = 17
m = 30
tiempo = tiempos(h, m)
print(tiempo)
def file_to_dict(file_name):
file_dict = {}
# open the file
with open(file_name) as f:
# loop through each line in the file
for line in f:
# remove new line character
key = line.rstrip()
# get the number of files in the directory
file_dict[key] = len(os.listdir(key))
return file_dict
def file_to_sorted_list(file_name):
file_dict = file_to_dict(file_name)
# return a list of directory name and number of files
return sorted(file_dict.items(), key=lambda kv: kv[1])
# test
for dir_name, number_of_files in file_to_sorted_list('directorios.txt'):
print(f'{dir_name} has {number_of_files} files')
from random import randint
def diceRoll(userGuess, numRoll):
if userGuess == numRoll:
return True
else:
return False
def main():
numRoll = randint(1, 6)
userGuess = int(input("Guess a number from 1 to 6: "))
if diceRoll(userGuess, numRoll):
print("You win!")
else:
print("You lose. Better luck next time!")
main()
You can use the following code to get the desired output.
function add(a, b) {
return a + b;
}
function subtract(a, b) {
return a - b;
}
function multiply(a, b) {
return a *
int main()
{
int a, b, c;
cin>>a>>b>>c;
if(a>b && a>c)
{
cout<<a<<" ";
if(b>c)
cout<<b<<" "<<c;
else
cout<<c<<" "<<b;
}
else if(b>a && b>c)
{
cout<<b<<" ";
if(a>c)
cout<<a<<" "<<c;
else
cout<<c<<" "<<a;
}
else if(c>a && c>b)
{
cout<<c<<" ";
if(a>b)
cout<<a<<" "<<b;
else
cout<<b<<" "<<a;
}
return 0;
}