regex explanationTue, 04 Jul 2023

def timeConversion(s): if s[-2:] == "AM": time = s[:-2] if time[:2] == "12": return "00" + time[2:] else: return time else: time = s[:-2] if time[:2] == "12": return time else: return str(int(time[:2]) + 12) + time[2:]

This is a solution to the problem below: Given a time in 12-hour AM/PM format, convert it to military (24-hour) time. Note: Midnight is 12:00:00AM on a 12-hour clock, and 00:00:00 on a 24-hour clock. Noon is 12:00:00PM on a 12-hour clock, and 12:00:00 on a 24-hour clock. Function Description Complete the timeConversion function in the editor below. It should return a new string representing the input time in 24 hour format. timeConversion has the following parameter(s): s: a string representing time in hour format Input Format A single string containing a time in -hour clock format (i.e.: or ), where and . Constraints All input times are valid Output Format Convert and print the given time in -hour format, where . Sample Input 0 07:05:45PM Sample Output 0 19:05:45

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