scanf(%d, &guess);

In Java, you would use the `Scanner` class to read user input, not `scanf`. Here's how you can do it:

```java
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.print("Enter your guess: ");
        int guess = scanner.nextInt();
        scanner.close();
        // Now you can use the guess variable
    }
}
```

However, if you're looking for a direct equivalent of `scanf` in Java, you can use the `BufferedReader` class along with `readInt()` method from `java.util.InputMismatchException` to handle the exception:

```java
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.InputMismatchException;

public class Main {
    public static void main(String[] args) {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        try {
            System.out.print("Enter your guess: ");
            int guess = Integer.parseInt(reader.readLine());
            // Now you can use the guess variable
        } catch (IOException e) {
            System.out.println("Error reading input.");
        } catch (NumberFormatException e) {
            System.out.println("Invalid input. Please enter a number.");
        }
    }
}
```

But keep in mind that `BufferedReader` is generally slower than `Scanner` for reading simple input like integers.