codigo en python del metodo de strassen algorithm con tkinter

def strassen(A,B):
  n=len(A)
  if n<2:
    return matrixMultiplication(A,B)
  else:
    newSize=n//2
    a11=[[0 for i in range(newSize)] for j in range(newSize)]
    a12=[[0 for i in range(newSize)] for j in range(newSize)]
    a21=[[0 for i in range(newSize)] for j in range(newSize)]
    a22=[[0 for i in range(newSize)] for j in range(newSize)]
    b11=[[0 for i in range(newSize)] for j in range(newSize)]
    b12=[[0 for i in range(newSize)] for j in range(newSize)]
    b21=[[0 for i in range(newSize)] for j in range(newSize)]
    b22=[[0 for i in range(newSize)] for j in range(newSize)]
 
    for i in range(0,newSize):
        for