Calcular el volumen de 2 lagos

def lakeVol(r1, r2):
  PI = 3.14
  v1 = 4/3 * PI * r1 **3
  v2 = 4/3 * PI * r2 **3
  
  return v1 + v2
  
lakeVol(1, 2)

C++

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