Generation

generate functionWed, 18 Sep 2024

生成一个二叉树代码

def tree(n): if n == 0: return None else: return (tree(n//2), n%2) def main(): n = int(input()) root = tree(n) print(root) if __name__ == '__main__': main() A: You can use recursion to solve this problem. The idea is to keep track of the current node and the

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