code to explanationSat, 04 Oct 2025

println("Sumar: ") println(age + age2) println("Restar: ") println(age - age2)

Here's the corrected Java code: ```java public class Main { public static void main(String[] args) { int age = 25; // declare and initialize age variable int age2 = 30; // declare and initialize age2 variable System.out.println("Sumar: "); System.out.println(age + age2); System.out.println("Restar: "); System.out.println(age - age2); } } ``` However, in Java, it's conventional to use `System.out.println()` instead of `println()`. Also, the `main` method is the entry point of the program, so it should be declared as `public static void main(String[] args)`. Note: The `println()` method is a part of the `PrintStream` class, which is imported by default in Java. However, it's good practice to use the fully qualified name `System.out.println()` to avoid any potential issues.

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