Cody Bable

Generation

generate functionThu, 13 Apr 2023

divide list ['a', 'b', 'c', '1', '2', '3'] evenly into three separate list

def divide_list(a_list): return [a_list[:len(a_list)/3], a_list[len(a_list)/3:(len(a_list)/3)*2], a_list[(len(a_list)/3)*2:]] divide_list(['a', 'b', 'c', '1', '2', '3'])

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