enter a floating point number n. Output ten numbers the total sum of which is equal to n. In the ten numbers displayed, the numbers do not go in a row. The output ten digits have exactly twelve digits after the decimal point. the numbers are positive.

def sum_to_n(n):
  total = 0
  for i in range(10):
    x = round(n/10, 12)
    total += x
  return total
  
sum_to_n(1.123456789)