x=4**2022-6*4**522+5*64**510-3*2**330-100 x is translated into the number system with the base 8. Determine the number of digits "7" in the record of this number

from math import log

def f(x):
    return int(log(x, 8)) + 1

def f1(x):
    return x % 8

def f2(x):
    return int(x / 8)

def g(x):
    if x < 8:
        return 0
    else:
        return g(f2(x)) + f1(x)

g(f(4**2022-6*4**522+5*64**510-3*2**330-100))